Question

The motion of particle of mass m is given by $y=ut+\frac{1}{2}g{t}^2$. The force acting on the particle is

• A. mg
• B. $\frac{mu}{t}$
• C. 2mg
• D. $\frac{2mu}{t}$

Answer 1

The correct option is A mg

Here $y=ut+\frac{1}{2}g{t}^2$.
$\therefore ,v=\frac{dy}{dt}=u+gt$
Acceleration, $a=\frac{dv}{dt}=g$
So, the net force acting on the particle is, F=ma=mg