The mutual inductance of a pair of coils, each of N turns, is M henry. If a current of I ampere in one of the coils is brought to zero in t second, the emf induced per turn in the other coil, in volt, will be

\frac{M I}{t}

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\frac{N M I}{t}

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\frac{M N}{I t}

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\frac{M I}{N t}

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Solution

The correct option is A $\frac{M I}{t}$
$E = \frac{d}{d t} (N M I)$
$\Rightarrow E = N M \frac{d I}{d t}$
$\Rightarrow E = \frac{N M I}{t}$

emf induced per unit turn $= \frac{E}{N} = \frac{M I}{t}$

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The mutual inductance of a pair of coils, each of N turns, is M henry. If a current of I ampere in one of the coils is brought to zero in t second, the emf induced per turn in the other coil, in volt, will be

The correct option is A MItE=ddt(NMI)⇒E=NMdIdt⇒E=NMItemf induced per unit turn =EN=MIt

The correct option is A $\frac{M I}{t}$
$E = \frac{d}{d t} (N M I)$
$\Rightarrow E = N M \frac{d I}{d t}$
$\Rightarrow E = \frac{N M I}{t}$

emf induced per unit turn $= \frac{E}{N} = \frac{M I}{t}$