The nth term of an AP is given by an=2+5n. The sum of the first 10 terms of the AP is
The sum of the first n terms of an AP with first term a and common difference d is given by
Sn=n2(2a+(n−1)d).
Given, an=2+5n.
∴a1=7, a2=12, a3=17...and so on.
∴a=a1=7 and d=a2−a1=5.
⟹S10=102(2(7)+(10−1)5)
=5(59)
=295
Thus, the sum of the first 10 terms of this AP is 295.