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Question

The nth terms of the series 3+7+13+21+ is

A
4n1
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B
nn+2n
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C
n2+n+1
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D
n2+2
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Solution

The correct option is C n2+n+1
S=3+7+13+21+....t(n)(1)
S= 3+7+13+.....t(n1)+t(n)(2)
Subtracting (2) from (1)
t(n)=3+4+6+8+12+.......2nt(n)=1+2+4+6+8+.......+20=1+2×n(n+1)2=1+n+n2

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