The names of reaction and intermediate species involved in the formation of $(C)$ , respectively, are:

friedel-Crafts alkylation, carbocation

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friedel-Crafts acylation, carbocation

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friedel-Crafts alkylation, radical anion

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friedel-Crafts acylation, radical anion

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Solution

The correct option is A friedel-Crafts alkylation, carbocation
$C H_{3} C H_{2} C H_{2} - B r F e B r_{3} ⟶ C H_{3} - C H_{2} C H_{2} - δ + B r - δ - F e B r_{3} ⟶ C H_{3} C H_{2} + C H_{2} + F e^{⊝} B r_{4}$
$F e B r_{3}$ is a lewis acid, react with bromopropane to form propanium cation which react with electron rich Benzene ring.
The intermediate formed is carbocation which is stabilized by resonance.

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In Friedel crafts alkylation and acylation the attacking reagent is an:

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