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Apparent Frequency:Listener Moving

The natural f...

Question

The natural frequency of a tuning fork P is 432 Hz. 3 beats/s are produced when tuning fork P and another tuning fork Q are sounded together. If P is loaded with wax, the number of beats increases to 5 beats/ s. The frequency of Q is

A

429 Hz

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B

435 Hz

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C

437 Hz

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D

427 Hz

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Solution

The correct option is A 435 Hz
Given: $f_{P} = 432 H z$
As P is loaded with wax, frequency of P decreases which led to increase in beat.
So, frequency of P is less than frequency of Q.
So, beat $= f_{Q} - f_{P}$
$3 = f_{Q} - 432$
$\Rightarrow f_{Q} = 435 H z$

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