Question

The natural frequency of system shown in figure above is

• A. 24.88 rad/s
• B. 12.44 rad/s
• C. 41.83 rad/s
• D. 20.91 rad/s

Answer 1

The correct option is A 24.88 rad/s

$\text{From above figure the equivalent spring constant,}\frac{13K}{21}$

$K^{\prime }=\frac{13\times 2000}{21}=1238.09\text{N/m}$

$m=2\text{kg}$

${\omega }_n=\sqrt{\frac{K^{\prime }}{m}}=24.88\text{rad/s}$