The natural numbers are arranged in rows as follows beginmatrix - - 111- 2 - - 311-4 - - - -6 II7 - 8 - 9 - 10end matrix - The sum of the numbers in the 20th row is

The correct option is C 4010 The 20^th row ends with 1 + 2 + …. + 20 = 20.21/2 = 210 The19^th row ends with 210 – 20 – 190. The 20^th begins with 191 The sum ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Definition of Function

The natural n...

Question

The natural numbers are arranged in rows as follows

$\begin{matrix} 1 2 & 3 4 & 5 & 6 7 & 8 & 9 & 10 \end{matrix}$ ………………………………………….

The sum of the numbers in the $20^{t h}$ row is

4010

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4020

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4120

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4210

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
4010

The $20^{t h}$ row ends with $1 + 2 + \dots . + 20 = \frac{20.21}{2} = 210$

The $19^{t h}$ row ends with 210 – 20 – 190. The $20^{t h}$ begins with 191

The sum of the numbers in the $20^{t h}$ row is $\frac{20}{2} [191 + 210] = 4010$

Suggest Corrections

Similar questions

Q. The natural numbers are divided into rows as follows

\begin{matrix} 1 2 & 3 & 4 5 & 6 & 7 & 8 & 9 \end{matrix}

The sum of the numbers in the

10^{t} h

row is

Q. The sequence N of natural numbers is divided into classes as follows

1

2 3 4
5 6 7 8 9
10 11 12 13 14 15 16
.......................................................
......................................................................
Find the sum of the numbers of n-th row

Q. 6 apples are arranged in a row. Find the total number of apples arranged in 4 rows in the carton.

Q. The set of natural numbers is divided into arrays of rows and columns in the form of matrices as

A_{1} = (1), A_{2} = (\begin{matrix} 2 & 3 4 & 5 \end{matrix}), A_{3} = ⎛ ⎜ ⎝ \begin{matrix} 6 & 7 & 8 9 & 10 & 11 12 & 13 & 14 \end{matrix} ⎞ ⎟ ⎠

... so on.
Find the value of

T_{r} (A_{10})

.
[Note:

T_{r} (A)

denotes sum of diagonal elements of

A

Q. The natural numbers are written in the form of a triangle as shown below :
The sum of numbers in all the n rows .

Join BYJU'S Learning Program

The natural numbers are arranged in rows as follows 12345678910 …………………………………………. The sum of the numbers in the 20th row is

The correct option is A 4010 The 20th row ends with 1+2+….+20=20.212=210 The19th row ends with 210 – 20 – 190. The 20th begins with 191 The sum of the numbers in the 20th row is 202[191+210]=4010

The natural numbers are arranged in rows as follows

$\begin{matrix} 1 2 & 3 4 & 5 & 6 7 & 8 & 9 & 10 \end{matrix}$ ………………………………………….

The sum of the numbers in the $20^{t h}$ row is

The correct option is A
4010

The $20^{t h}$ row ends with $1 + 2 + \dots . + 20 = \frac{20.21}{2} = 210$

The $19^{t h}$ row ends with 210 – 20 – 190. The $20^{t h}$ begins with 191

The sum of the numbers in the $20^{t h}$ row is $\frac{20}{2} [191 + 210] = 4010$