Question

The natural water content as a sample taken from soil deposit was found to be 15 %. It has been calculated that the maximum density of soil will be obtained when the water content reaches 21.5%. How much water must be added to each 500 kN as soil (in its natural state) in order to increase the water content to 21.5 %. Take G= 2.75.

• A. 9.8 kN
• B. 28.26 kN
• C. 20.98 kN
• D. 26.85 kN

Answer 1

The correct option is B 28.26 kN

Given data

$W_{natural}=0.15$

$W_{saturation}=0.215$

As we know that

$W_s=\left(\frac{W_T}{1+w}\right)$

$W_s=\frac{500}{1.15}=434.78kN$

$W_T$ when w = 0.215

$W_{Total}=434.78\times (1+0.215)=528.26kN$

So water added =$528.26-500=28.26kN$