The natural water content of the soil sample was found to be 40% , specific gravity is 2.7 and void ratio 1.2 then the degree of saturation of the soil will be

100%

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69%

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87%

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90%

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Solution

The correct option is D 90%
(d)
$e = \frac{w G_{s}}{S}$

$∴$ Degree of saturation,

$S = \frac{w G_{s}}{e} = \frac{0.4 \times 2.7}{1.2}$

= $0.9 \times 100$ = 90%

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The natural water content of the soil sample was found to be 40% , specific gravity is 2.7 and void ratio 1.2 then the degree of saturation of the soil will be

The correct option is D 90%(d) e=wGsS ∴ Degree of saturation, S=wGse=0.4×2.71.2 = 0.9×100 = 90%

The correct option is D 90%
(d)
$e = \frac{w G_{s}}{S}$

$∴$ Degree of saturation,

$S = \frac{w G_{s}}{e} = \frac{0.4 \times 2.7}{1.2}$

= $0.9 \times 100$ = 90%