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Question
The nature of resultant solution when 20ml, 0.05 N NaoH and 0.1 N ,10 ml HCl is :
The nature of resultant solution when 20ml, 0.05 N NaoH and 0.1 N ,10 ml HCl is :
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Solution
The correct option is C neutral
0.05 M NaOH = 0.05 N NaOH as number of equivalents = 1 for NaOH
moles of NaOH=0.05 N×20 ml=1 m mole
moles of HCl=0.1 N×10 ml=1 m mole
Number of moles of acid and base are equal thus solution is neutral.
0.05 M NaOH = 0.05 N NaOH as number of equivalents = 1 for NaOH
moles of NaOH=0.05 N×20 ml=1 m mole
moles of HCl=0.1 N×10 ml=1 m mole
Number of moles of acid and base are equal thus solution is neutral.
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