The nature of the roots of the equation 8x3+36x2+54x+27=0 is:
A
One real and two imaginary
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B
All real and distinct
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C
Real and equal
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D
Real and positive
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Solution
The correct option is C Real and equal Let f(x)=8x3+36x2+54x+27 ⇒f′(x)=24x2+72x+54 ⇒f′(x)=0⇒x=−32,−32 f′′(x)=48x+72
Clearly, f′′(−32)=0=f(−32) ∴ Roots of f(x)=0 are real and equal.