The nature of x and y in third quadrant of cartesian plane is a) x is greater than 0, y is lesser than 0. b) x is lesser than 0, y is lesser than 0. c) x is greater than 0,y is greater than 0 d) x is lesser than 0, y is greater than 0.
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Solution
Dear student
b) option is right because in the third quadrant both abscissa and ordinate are negative, i.e. less than zero. (-x,-y)
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