Question

The needle of a dip circle shows an apparent dip of ${45}^o$ at a place and ${60}^o$ when the circle is rotated through ${90}^o$. The true dip is

• A. $co{s}^{-1}\left(\frac{1}{\sqrt{3}}\right)$
• B. $co{s}^{-1}\left(\frac{2}{\sqrt{3}}\right)$
• C. $co{s}^{-1}\left(\frac{1}{2}\right)$
• D. $co{s}^{-1}\left(\frac{1}{\sqrt{2}}\right)$

Answer 1

The correct option is B $co{s}^{-1}\left(\frac{2}{\sqrt{3}}\right)$

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