The negation of q -p - r is -A- - q -p - rB- - q -p - rC- - q -p - rD- - q -p - r

The correct option is B ∼ q ∧ (p ∧ r) ∼ (p ∨ q) = ∼ p ∧∼ q ∴ ∼(q ∨∼ (p ∧ r)) = ∼ q ∧∼(∼(p ∧ r)) = ∼ q ∧ (p ∧ r) ...

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Negation

The negation ...

Question

The negation of $q \lor \sim (p \land r)$ is ___.

$\sim q \land \sim (p \land r)$

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$\sim q \land (p \land r)$

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$\sim q \lor (p \land r)$

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$\sim q \lor \sim (p \land r)$

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Solution

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Similar questions

q \lor \sim (p \land r)

\sim p \to (q \lor r)

Negation of the statement $\sim p \to (q \lor r)$ is

(p \land q) \to (\sim p \lor r)

p \to (q \lor r)

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