The negation of the compound statement p - p - q is -

∼ (p ∨ q) = ∼ p ∧ ∼ q ∼ (p ∨ (∼ p ∨ q)) = ∼ p ∧∼ (∼ p ∨ q) = ∼ p ∧ (p ∧ ∼ q) = (p ∧∼ q) ∧∼ p ...

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Distributive Law

The negation ...

Question

The negation of the compound statement $p \land (\sim p \lor q)$ is ___.

$(p \land \sim q) \land \sim p$

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$(p \land \sim q) \lor \sim p$

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$(\sim p \land \sim q) \land p$

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$(p \lor \sim q) \land \sim p$

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Solution

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The negation of the compound statement $p \lor (\sim p \lor q)$ is ___.

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