Question

The negation of the statement "if $5>7$ then, $6<4$"

• A. $(5>7)\wedge (6\ge 4)$
• B. $(5>7)\vee (6\le 4)$
• C. $(5\le 7)\vee (6\le 4)$
• D. $(5\le 7)\wedge (6\le 4)$

Answer 1

The correct option is A $(5>7)\wedge (6\ge 4)$

Let $p:5>7;q:6<4$;
We know that the negation of implication is given as $\sim (p\to q)=p\wedge \sim q$
So the negation of the statement "if $5>7$ then, $6<4$" is $(5>7)\wedge (6\ge 4)$