The negation of the statement p - q - r is A- P - qB- - p - q - qC - p - q - rD- -p - q - r

The correct option is C (∼ p ∧∼ q)∨∼ r∼ [(p ∨ q)∧ r]≡∼ (p ∨ q)∨∼ r ≡ (∼ p ∧∼ q)∨∼ r ...

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Negation

The negation ...

Question

The negation of the statement $(p \lor q) \land r$ is

(\sim p \lor \sim q) \lor \sim q

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(\sim p \land \sim q) \lor \sim r

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\sim (p \lor q) \to r

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p \land q

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Solution

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(p \lor q) \land r

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The negation of $p \land q \to p \lor q i s$

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