The negation of the statement p - q - r is A- - p - q - qB- - p - q - rC- P - qD- -p - q - r

The correct option is B (∼ p ∧∼ q)∨∼ r∼ [(p ∨ q)∧ r]≡∼ (p ∨ q)∨∼ r ≡ (∼ p ∧∼ q)∨∼ r ...

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Negation

The negation ...

Question

The negation of the statement $(p \lor q) \land r$ is

(\sim p \lor \sim q) \lor \sim q

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(\sim p \land \sim q) \lor \sim r

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\sim (p \lor q) \to r

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p \land q

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Solution

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