The negation of the statement p - q - q isA- - p - q - qB- p - q - qC- - p - q - qD- p - q - q

The correct option is C (∼ p ∧ q) ∨∼ q ∼((p ∨∼ q) ∧ q) = ∼(p ∨∼ q) ∨∼ q = (∼ p ∧ q) ∨∼ q ...

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Negation

The negation ...

Question

The negation of the statement $(p \lor \sim q) \land q$ is

$(\sim p \lor q) \land \sim q$

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$(p \land \sim q) \lor q$

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$(\sim p \land q) \lor \sim q$

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$(p \land \sim q) \lor \sim q$

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Solution

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(p \lor q) \land r

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