The net flux of the electric field through the surface due to $q_{3}$ and $q_{4}$ is :

zero

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positive

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negative

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cannot say

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Solution

The correct option is A zero
Since the two charges $q_{3}$ and $q_{4}$ are not enclosed within the closed surface. Thus net flux through surface due to charge $q_{3}$ and $q_{4}$ will be zero.

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q_{4}

The electric flux through the surface S as due to all the charges as shown in following figure is $\frac{q_{1} + q_{3} - q_{2} - q_{4}}{ϵ_{0}}$

S

q_{1} = q_{4} = 3.1 n C, q_{2} = q_{5} - 5.9 n C, q_{3} = - 3.1 n C

S

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