Question

The net requirement of assimilatory power for the formation of 6 hexose molecules in maize plant is:

• A. 72 ATP, 48 NADPH
• B. 90 ATP, 60 NADPH
• C. 108 ATP, 72 NADPH
• D. 180 ATP, 72 NADPH

Answer 1

The correct option is D 180 ATP, 72 NADPH

Maize exhibits Kranz anatomy in its leaf. Therefore, the $C_4$ pathway is present. For each cycle of $C_4$pathway, the number of ATPs produced are 30 and the number of NADPH are 12. For synthesis of six hexose molecules, the number of ATPs and NADPH produced are 180 (30✖6 = 180) and 72 (12✖6 = 72), respectively.