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Byju's Answer

Standard XII

Physics

Inductors in Circuits

The network s...

Question

The network shown in the figure is part of a complete circuit. If at a certain instant, the current I is 5A and it is decreasing at a rate of $10^{3} A s^{- 1}$ then $V_{B} - V_{A}$ equals

20 V

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15 V

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10 V

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5 V

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Solution

The correct option is B $15 V$
$V_{A} - V_{B} = I R - 15 - L \frac{d i}{d t}$
$V_{A} - V_{B} = 5 \times 1 - 15 - 5 \times 10^{- 3} \times 10^{3}$
(since the current is decreasing, the polarity of induced e.m.f is such that it intends to increase the current)
$V_{A} - V_{B} = - 15 V$
$V_{B} - V_{A} = 15 V$

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