The neutral atom of an element $E$ consists $12$ electrons in it $1.$ Name element $E$ and in which period and group is $E$ placed. $2.$ How many electrons it needs to lose or gain to achieve Noble gas configuration? $3.$ What will be the nature of oxides (acidic/ basic) of $E$ ?
Justify your answer.

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Solution

Name of element magnesium $\to$
Electronic configuration $= 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$
For noble gas configuration magnesium can lose two electron
Nature of oxide is basic

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The neutral atom of an element E consists 12 electrons in it 1. Name element E and in which period and group is E placed. 2. How many electrons it needs to lose or gain to achieve Noble gas configuration? 3. What will be the nature of oxides (acidic/ basic) of E?Justify your answer.

Name of element magnesium →Electronic configuration =1s22s22p63s2For noble gas configuration magnesium can lose two electronNature of oxide is basic

Name of element magnesium $\to$
Electronic configuration $= 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$
For noble gas configuration magnesium can lose two electron
Nature of oxide is basic