The neutral temperature is 'a' and the inversion temperature is 'b' then the temperature of the cold junction will be

(- 2 a - b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{(2 a - b)}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 a + b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 a - b)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $(2 a - b)$
$T_{n} - T_{c} = T_{i} - T_{n}$

$T_{n}$ = temperature at neutral junction
$T_{c}$ = temperature at cold junction
$T_{i}$ = temperature at inversion junction
so
$a - T_{c} = b - a$
hence $T_{c} = (2 a - b)$

Suggest Corrections

Similar questions

\sqrt{a^{2} + b} = a + \frac{b}{2 a +} \frac{b}{2 a +} \dots

\sqrt{a^{2} - b} = a - \frac{b}{2 a -} \frac{b}{2 a -} \dots

(2 a + b)^{2} + 5 (2 a + b) + 6

(2 a + b + 3) (2 a + b + 2)

1

0

Join BYJU'S Learning Program