Question

The neutral temperature of a thermocouple is 275${}^{o}C$ and the temperature of inversion is 600${}^{o}C$. The temperature of the cold junction is

• A. 50${}^{o}C$
• B. 25${}^{o}C$
• C. -25${}^{o}C$
• D. -50${}^{o}C$

Answer 1

The correct option is D -50${}^{o}C$

For thermocouples,
${\theta }_n=\frac{({\theta }_i+{\theta }_c)}{2}$
Where, ${\theta }_n$ is the neutral temperature, ${\theta }_i$ is the temperature of inversion and ${\theta }_c$ is the temperature of cold junction.
${\theta }_c=2\left({\theta }_n\right)-{\theta }_i$
${\theta }_c=2\left(275\right)-600=550-600=-{50}^{\circ }C$