Question

The no. of moles of $KMn{O}_4$ that will be needed to react completely with one mole of ferrous oxalate in acidic
solution is x. Then the value of 5x will be:

• A. 0.6
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is C 3

$\stackrel{+2}{F}e{\stackrel{+3}{C}}_2{O}_4+K\stackrel{+7}{M}n{O}_4⟶F{e}^{3+}+\stackrel{+4}{C}{O}_2+M{n}^{2+}$
n-factor for $Fe{C}_2{O}_4=1+2=3$
Since,
no of eqv. of $Fe{C}_2{O}_4$ = no of eqv. of $KMn{O}_4$
$\Rightarrow 1\times 3=n\times 5$
$\Rightarrow n=\frac{3}{5}=x$