The non-metals undergoing disproportionation are____________.

P_{4}

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C l_{2}

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I_{2}

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Solution

The correct options are
A $C l_{2}$
B $P_{4}$
C $I_{2}$
Except Fluorine (the highest electronegative element in the period table and it shows only one oxidation state of -1), others show multiple oxidation state and hence, can undergo disproportionation reaction (oxidation and reduction simultaneously within a single reaction).
Phosphorus can show oxidation state from -3 to +5
Chlorine can show oxidation state from -1 to +7
Iodine can show oxidation state from -1 to +7
Hence, $A, B, C$ are correct options.

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N a O H

P_{4}

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N H_{4} N O_{3} Δ - ---- \to N_{2} O + H_{2} O

P_{4} Δ - ---- \to P H_{3} + H P O_{2}^{⊖}

P {C l}_{5} Δ - ---- \to P {C l}_{3} + {C l}_{2}

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P_{4} (s) + 6 C l_{2} (g) ⇋ 4 P C l_{3} (g)

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