The non parametric vector equation of a plane passing through three non collinear points whose position vectors are $\to a, \to b, \to c$ is:

[\to r - \to a \to b - \to a - \to c - \to a] = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[\to r \to a \to b] = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[\to r \to b \to c] = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[\to a \to b \to c] = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $[\to r - \to a \to b - \to a - \to c - \to a] = 0$
Given position vectors of three points are $\to a, \to b$ and $\to c$
Let any vector $\to r$ lies in the plane contained by above three vector
So, vectors $\to r - \to a, \to b - \to a$ and $\to c - \to a$ are coplaner
Hence $[\to r - \to a \to b - \to a \to c - \to a] = 0$

Suggest Corrections

Similar questions

\to a

\to b

\to v

\to a

\to u

\to v

\to a, \to b, \to c

A

¯ ¯ ¯ a, ¯ ¯ b, ¯ ¯ c

2 ¯ ¯ ¯ a - 7 ¯ ¯ b + 5 ¯ ¯ c = 0

R

¯ ¯ ¯ a, ¯ ¯ b, ¯ ¯ c

l ¯ ¯ ¯ a + m ¯ ¯ b + n ¯ ¯ c = ¯ ¯ ¯ 0

Derive the equation of a plane passing through three non-collinear points both in the vector and cartesian form .

Join BYJU'S Learning Program