The non-stoichiometric compound Fe0.94O is formed when x% of Fe2+ ions are replaced by as many 23Fe3+ ions, x is ?
6
12
15
18
Number of Fe3+ ions replacing x Fe2+ ions =2x3 Vacancies of cations =x−2x3=x3 But x3=1−0.94=0.06 Or, x=0.06×3=0.18=18%
The non-stoichiometric compound Fe0.94O is formed when x% of Fe2+ ions are replaced by Fe3+ ions then x is