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Question

The non-stoichiometric compound Fe0.94O is formed when x% of Fe2+ ions are replaced by as many 23Fe3+ ions, x is ?


A

6

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B

12

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C

15

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D

18

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Solution

The correct option is D

18


Number of Fe3+ ions replacing x Fe2+ ions =2x3
Vacancies of cations =x2x3=x3
But x3=10.94=0.06
Or, x=0.06×3=0.18=18%


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