The normal at any point q to the curve x = a (cos q + q sin q), y = a (sin q - q cos q)
is at distance from the origin that is equal to... .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
a

Suggest Corrections

Similar questions

Show that the normal at any point $θ$ to the curve $x = a c o s θ + a θ, y = a s i n θ - a θ c o s θ$ is. at a constant distance from the origin.

x = a (cos θ + θ sin θ)

y = a (sin θ - θ cos θ)

θ

x = a cos θ + a θ sin θ

y = a sin θ - a θ cos θ

t

x = c o s t + a t s i n t

y s i n t - a t c o s t

Join BYJU'S Learning Program