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Question

The normal boiling of water is 373K. Vapour pressure of water at temperature T is 19 mm Hg. If enthalpy of evaporation is 40.67kJ/mol, then temperature T would be:
(Use log2=0.3,R=8.3JK1)

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Solution

By Clausius- Clayperon Equation
lnP2P1=ΔHR[1T11T2]
Here, T2=373K,P2=760mmHg,T1=T & P1=19
ln(76019)=406708.3[1T1373]
T=291.3K

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