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Question

The normal to the curve x2 = 4y passing (1, 2) is

(A) x + y = 3 (B) x āˆ’ y = 3

(C) x + y = 1 (D) x āˆ’ y = 1

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Solution

The equation of the given curve is x2 = 4y.

Differentiating with respect to x, we have:

The slope of the normal to the given curve at point (h, k) is given by,

āˆ“Equation of the normal at point (h, k) is given as:

Now, it is given that the normal passes through the point (1, 2).

Therefore, we have:

Since (h, k) lies on the curve x2 = 4y, we have h2 = 4k.

From equation (i), we have:

Hence, the equation of the normal is given as:

The correct answer is A.


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