wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The normal to the curve y(x2)(x3)=x+6 at the point where the curve intersects the y-axis passes through the point

[1 mark]

A
(12,12)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(12,12)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(12,13)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(12,13)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (12,12)
y=x+6(x2)(x3)
Coordinates of point of intersection with y-axis is (0,1)
y=x+6x25x+6
y=(x25x+6)(2x5)(x+6)(x25x+6)2
yx=0=6(30)36=1
Then, slope of normal at (0,1) is 1
Equation of normal passing through (0,1) is y1=1(x0)
i.e., x+y=1
Thus, the normal passes through (12,12).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon