Question

The normality and volume strength of a solution made by mixing $1.0$ L each of $5.6$ vol and $11.2$ vol $H_2{O}_2$ solution are:

• A. $1N,5.6$ vol
• B. $1.5N,5.6$ vol
• C. $1.5N,8.4$ vol
• D. $1N,8.4$ vol

Answer 1

Answer: (C)

$1.5N,8.4$ vol

Volume strength = Normality $\times 5.6$

We are mixing $1L$ of $5.6$ vol $H_2{O}_2$ and $1L$ of $11.2$ vol $H_2{O}_2$.

$1L$ of $5.6$ vol $H_2{O}_2$ has normality $=\frac{5.6}{5.6}=1N$

$1L$ of $11.2$ vol $H_2{O}_2$ has normality $=\frac{11.2}{5.6}=2N$

On mixing both solutions, the normality of solution $=\frac{3}{2}=1.5N$.

Now the volume strength $=1.5\times 5.6=8.4$ vol.