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Question

The normality of 0.3 M phosphorous acid (H3PO3), phosphoric acid (H3PO4) and boric acid (H3BO3) respectively are:

A
0.9, 0.9, 0.9
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B
0.6, 0.9, 0.9
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C
0.6, 0.9, 0.3
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D
0.9, 0.9, 0.1
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Solution

The correct option is C 0.6, 0.9, 0.3
n-factor for H3PO3=2
(as only 2 hydrogen atoms are replaceable)
Normality = molarity × n-factor
=0.3×2=0.6 N

n-factor for H3PO4=3
Normality = molarity × n-factor
=0.3×3=0.9 N

n-factor for H3BO3=1
Normality = molarity × n-factor
=0.3×1=0.3 N

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