The normality of $0.3$ M phosphorous acid $(H_{3} P O_{3})$ is :

0.1

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0.9

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0.3

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0.6

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Solution

The correct option is D 0.6
Phosphorous acid is ibasic acid as it contains 2 replaceable H atoms.
$N o r m a l i t y = B a s i c i t y \times m o l a r i t y$
$N o r m a l i t y = 2 \times 0.3 = 0.6 N$

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