The normality of $0.3 M$ phosphorus acid $(H_{3} P O_{3})$ is

0.1

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0.9

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0.3

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0.6

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Solution

The correct option is B $0.6$
$N = G E \times M$
So $N = G E \times M = 2 \times 0.3 = 0.6$
Hence option D is correct.

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