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Question

The normality of 1.11 g of CaCl2 dissolved in 250 mL solution is .

A
0.1 N
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B
0.25 N
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C
0.08 N
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D
0.3 N
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Solution

The correct option is C 0.08 N

Normality = Gram equivalents of soluteVolume of solution (in litre)

Equivalent mass =Molecular MassCharge on ion×number of ions
[CaCa2++2e]
[Cl2+2e2Cl]
Either way, the denominator would be 2, please check this carefully!

= 1112 = 55.5
No of gram equivalents = 1.1155.5
Normality = 1.1155.52501000=0.08 N


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