Question

The normality of $26$% (wt/vol) solution of ammonia ($density=0.855$) is approximately:

• A. $1.5$
• B. $0.4$
• C. $15.3$
• D. $4$

Answer 1

The correct option is C $15.3$

The equivalent weight of ${NH}_3=17$

The concentration of $N{H}_3$ solution is $26$% (wt/vol).

So 100 ml of ${NH}_3$ solution will have 26 g of ${NH}_3$.

The number of gram equivalents of ${NH}_3=\frac{\text{Weight}}{\text{Equivalent weight}}=\frac{26}{17}geq=1.53geq$

The volume of solution $=100ml=\frac{\text{100 mL}}{\text{1000 mL/L}}=0.1L$

$\therefore$ Normality of $N{H}_3=\frac{\text{number of gram equivalents of}N{H}_3}{\text{volume of solution (in L)}}=\frac{1.53\text{g eq}}{0.1\text{L}}=15.3N$

Hence, option C is correct.