The normality of a $26$ % mass/volume solution of ammonia (density $0.85 g / m L)$ is approximately.

1.5

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4.0

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0.4

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15.3

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Solution

The correct option is C $15.3$
$M a s s = D e n s i t y \times v o l u m e = 0.85 \times 1 = 0.85$ grams
0.85 grams is the mass of $N H_{4} O H$
The amount of $N H_{3}$
$= \frac{26}{100} \times 0.850.221$ grams
$N o r m a l i t y = \frac{a m m o u n t o f $ N H_{3} $}{E q i v a l e n t m a s s o f $ N H_{3}} \times v o l u m e = \frac{0.221}{17} \times 1000 = 15.3$
Hence option D is correct.

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