The normality of a solution of sulphuric acid is 0.1 N. Its molarity will be:

0.2M

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0.1M

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0.05M

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0.025M

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Solution

The correct option is C
0.05M

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Q. Sulphuric acid reacts with sodium hydroxide as follows

H_{2} S O_{4}

2 N a O H

\to

N a_{2} S O_{4}

2 H_{2} O

When 1 L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained is ?

Sulphuric acid reacts with sodium hydroxide as follows

$H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O$

When 1L of 0.1M sulphuric acid solutoin is allowed to react with 1L of 0.1M sodium hydroxide solutoin, the amount of sodium sulphate formed and its molarity in the solution obtained is ?

(a) $0.1 m o l L^{- 1}$ (b) $7.10 g$

Q. A sulphuric acid solution has

p H = 3

. Its normality is:

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The normality of a solution of sulphuric acid is 0.1 N. Its molarity will be:

The correct option is C 0.05M

The correct option is C
0.05M