The normals at three points P, Q, R of the parabola y2=4ax meet in (h, k). The centroid of triangle PQR lies on
A
x=0
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B
y=0
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C
x=−a
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D
y=a
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Solution
The correct option is By=0 y2=4ax.............(1)
Normals are drawn on P,Q,R but from (h,k)
We know that centroid of triangle formed joining fleet of normals drawn from a point always lies on the axis of parabola. So, (h,k) lies on axis of Parabola y2=4ax ie.