Question

The Novolac polymer has mass of $963g$. The number of monomer units present in it are

• A. 9
• B. 9.0
• C. 9.00

Answer 1

Answer: (A), (B), (C)

Novolac is


Monomer unit of Novolac is
its molecular mass is $124\text{amu}$.
Upon considring molecular weight of polymer as $963\text{amu}$ (In question its given as 963 gram)
Now if during formation of Novolac, $(n-1)$ unit of water are removed then
$n\times 124=963+[18\times (n-1\left)\right]$
$n=9$