The nth term general term of an arithmetic progression- a1- a2- a3- - an- - where a2-a1-a3-a2- -d is-

The correct option is C an = a1 + (n – 1)d ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Sum of n Terms

The nth term ...

Question

The n^th term (general term) of an arithmetic progression, a₁, a₂, a₃, …, a_n, … where a₂ –a₁ = a₃ – a₂ = …. = d is:

a_n = a₁ – (n – 1)d

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a_n= a_n-1– (n – 1)d

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a_n = a₁ + (n – 1)d

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a_n = a_n-1 + (n-1)d

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
a_n = a₁ + (n – 1)d

Suggest Corrections

Similar questions

If $a_{1}, a_{2}, a_{3}, \dots, a_{n}$ are in arithmetic progression, where $a_{1} > 0$ for all i.
Prove that $\frac{1}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{1}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \dots + \frac{1}{\sqrt{a_{n - 1}} + \sqrt{a_{n}}} = \frac{n - 1}{\sqrt{a_{1}} + \sqrt{a_{n}}}$