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Question

The nth term of a series is given to be 3+n4, find the sum of 105 terms of this series.

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Solution

Putting n=1,2,3,______ in Tn=(3+n)/4
We get the series as 1,54,32,_______
a=1,d=14.
S105=1052[2.1+(104)14]
=(105/2)×28=1470.

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