The nth term of an AP is (7 - 4n). Find its common difference.

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Solution

Given the nth term is 7 - 4n

$a_{n} = 7 - 4 n$

Put n = 1,

$a_{1} = 7 - 4 \times 1 = 7 - 4 = 3$

Put n = 2,

$a_{2} = 7 - 4 \times 2 = 7 - 8 = - 1$

Common difference $d = a_{2} - a_{1} = - 1 - 3 = - 4$

So common difference of the AP is -4

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The nth term of an AP is (7 - 4n). Find its common difference.

Given the nth term is 7 - 4n an=7−4n Put n = 1, a1=7−4×1=7−4=3 Put n = 2, a2=7−4×2=7−8=−1 Common difference d=a2−a1=−1−3=−4 So common difference of the AP is -4

Given the nth term is 7 - 4n

$a_{n} = 7 - 4 n$

Put n = 1,

$a_{1} = 7 - 4 \times 1 = 7 - 4 = 3$

Put n = 2,

$a_{2} = 7 - 4 \times 2 = 7 - 8 = - 1$

Common difference $d = a_{2} - a_{1} = - 1 - 3 = - 4$

So common difference of the AP is -4