Question

The nth term of the A.P. is $2n-5$, then the series is :

• A. $-3,-1,1,....$
• B. $3,1,-1,...........$
• C. $2,5,8,.........$
• D. $1,7,13,........$

Answer 1

The correct option is A $-3,-1,1,....$

Given, $a_n=2n-5$
$\therefore a_1=2\left(1\right)-5=-3$
$a_2=2\left(2\right)-5=-1$
$a_3=2\left(3\right)-5=1$
Therefore, the given AP is
$-3,-1,1,...$
Option A is correct.