The nth term of the series $3.8 + 6.11 + 9.14 + 12.17 + . . . .$ will be

3 n (n + 5)

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3 n (3 n + 5)

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n (3 n + 5)

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n (n + 5)

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Solution

The correct option is B $3 n (3 n + 5)$
$3.8 + 6.11 + 9.14 + 12.17 + . . . . . . .$
$3, 6, 9, . . . . .$
$T_{n} = 3 + (n - 1) 3$
$= 3 + 3 n - 3$
$3 n$
$8, 11, 14, 17, . . . .$
$T_{n} = 8 + (n - 1) 3$
$= 8 + 3 n - 3$
$= 3 n + 5$
$T n = 3 n (3 n + 5)$

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