The nuclear process that transmutes uranium $- 238$ into $t h o r i u m - 234$ :

Gamma decay

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Nuclear fusion

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Alpha decay

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Positron emission

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Nuclear fission

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Solution

The correct option is C Alpha decay
The nuclear process that transmutes uranium−238 into thorium−234 is alpha decay. Alpha particles are helium nuclei $_{2}^{4} H e$ .
$_{92}^{238} U \to_{90}^{234} +_{2}^{4} H e$

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Similar questions

_{92} U^{238} \to_{90} T h^{234} + X

The radioactive decay of uranium into thorium is represented by the equation
$_{92}^{238} U \to_{90}^{234} T h + x$
What is x?

_{92}^{238} U

_{90}^{234} T h

_{2}^{4} H e

_{92}^{238} U

_{90}^{234} T h

_{92}^{238} U \to_{90}^{234} T h +_{2}^{4} H e + e n e r g y

238

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